23x2y6z−3(52x5y4z−7)\frac{2}{3}x^2y^6z^{-3}\left(\frac{5}{2}x^5y^4z^{-7}\right)32x2y6z−3(25x5y4z−7)
x2−3x−40≥0x^2-3x-40\ge0x2−3x−40≥0
∫2x−325−x2dx\int\frac{2x-3}{\sqrt{25-x^2}}dx∫25−x22x−3dx
3sinx = 3−3cosx3sinx\:=\:3-3cosx3sinx=3−3cosx
cos2x1−sinx=(cscx+1)cscx\frac{cos^2x}{1-sinx}=\frac{\left(cscx+1\right)}{cscx}1−sinxcos2x=cscx(cscx+1)
x−x5x-x^5x−x5
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