$0\left(2\cdot0\right)^{0-1}$
$225x^4-1$
$-2+1-2-1-1-1-1+0+0$
$2xy^2+4=2\left(3-x^2y\right)y'$
$\left(x^3y^4\cdot2x^2y^3\right)^2$
$x\frac{d}{dx}\left(y\right)-2y=0$
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