$d^2-41=8$
$x^16-y^16$
$\frac{dy}{dx}=.6y\left(1-\frac{y}{1050}\right)$
$\frac{dy}{dx}=10x^2+A$
$\frac{dy}{dx}=\frac{4y-3x}{2x-x}$
$\int\left(16+x^2\right)^{-\frac{1}{2}}dx$
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