$\left(x-y+3\right)^2$
$\lim_{x\to0}\left(\frac{1}{x^5}-\frac{1}{x^3}\right)$
$\left(a^2\right)\left(-2ab\right)\left(-7b^2\right)$
$\int\frac{5x^2}{\left(x^2+4x+3\right)}dx$
$\sqrt[4]{\frac{256}{16}}$
$\sqrt{5z}\cdot\sqrt{3z}$
$\left(6x^{-15}\right)\left(-8x^9\right)$
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