$y=\frac{3}{2}x^4+x$
$\frac{27-t^6}{3+n}$
$y=\left[ln\left(\left(x-1\right)^5\right)\left(x^2+1\right)^6\right]$
$x^2+\:10x\:+\:6\:=\:0$
$\frac{\left(-1\right)^{n+1}}{n.2^n}$
$\frac{1}{3}+\frac{2}{2x+1}=\frac{3}{2x+1}$
$\left(8x-6y\right)\left(8x-3y\right)$
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