$14\cdot2700$
$\frac{d}{dy}e^{3z}=xyz$
$\left(-x^3+5x^2+2x-5\right)=\left(x-5\right)$
$\:\frac{1-\tan^2\:u}{1+\tan^2\:u}+1\:=\:2\:\cos^2\:u\:$
$\int\left(\frac{e^{2x}-1}{8x}\right)dx$
$\int\left(tan\:3x+sec\:3x\right)dx$
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