$\frac{dy}{dx}=\frac{xy^3}{\sqrt{1+y^2}}$
$1,44\cdot50$
$2^3\cdot\sqrt{64}$
$\frac{dy}{dx}\:x^2=y\left(y+3\right)$
$16x^2-81\left(4x-9\right)\left(4x+9\right)$
$64x^2+16xy+y^2$
$\left(2x^{2\:}+5x-6\right)\cdot\left(3x^2-6x+3\right)$
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