Learn how to solve limits by l'hôpital's rule problems step by step online. Find the limit of 7sin(6x)ln(6x) as x approaches 0. The limit of the product of a function and a constant is equal to the limit of the function, times the constant: \displaystyle \lim_{t\to 0}{\left(at\right)}=a\cdot\lim_{t\to 0}{\left(t\right)}. Rewrite the product inside the limit as a fraction. If we directly evaluate the limit 7\lim_{x\to0}\left(\frac{\ln\left(6x\right)}{\frac{1}{\sin\left(6x\right)}}\right) as x tends to 0, we can see that it gives us an indeterminate form. We can solve this limit by applying L'Hôpital's rule, which consists of calculating the derivative of both the numerator and the denominator separately.

Find the limit of 7sin(6x)ln(6x) as x approaches 0