$3x^2+4x+2^2$
$-2=2x^2-5x$
$\lim_{x\to-\infty}\left(\frac{3x^2+9x}{x^2-9}\right)$
$\left(m-n+p\right)-\left(3n+4m+5p\right)\:$
$\frac{1}{3}ca^{-4}$
$\frac{d}{dx}\left(\frac{\left(4x^2-3\right)\left(5x+2\right)}{x\left(3x+1\right)}\right)$
$2p^2-p+10=0$
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