$-2+5x^3+3y^2+4x^3-7+3-5x^3$
$\left(2y+4\right)\left(2y+3\right)$
$\int\frac{x+10}{x^2+2x-8}dx$
$-\left(-75-15\right)-\left(-200-380\right)-\left(420-150\right)$
$m\left(t\right)=\:\left(t^2-5x+3\right)^{\frac{-2}{3}}$
$63+2z-z^2$
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