$\frac{d}{dx}\left(4\pi\left[r\left(t\right)\right]^2\right)$

$2x^3-2>0$

$x^2+2x=c$

$\cot^2\left(x\right)\cdot\tan^2\left(x\right)=1$

$\sin\left(t\right)\cos\left(v\right)=\frac{1}{2}\left(\sin\left(t+v\right)+\sin\:\left(t-v\right)\right)$

$1-4p+1-7p$