$5-\left[7-2-\left(1-9\right)-3+12\:\right]+4$
$\frac{x^2}{\left(x-3\right)^2}$
$5x^2+20x-17$
$9x-17=2x+32$
$\int\frac{x+32}{x^2+x-12}dx$
$\frac{3^{x-2}}{8}2^{x-2}=0$
$\int\frac{3x^2-8x-36}{x^4-16}dx$
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