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Exercise

$\lim_{x\to1}\left(\left(\frac{2cos^2x+3cosx-2}{2cosx-1}\right)\right)$

Step-by-step Solution

1

Evaluate the limit $\lim_{x\to1}\left(\frac{2\cos\left(x\right)^2+3\cos\left(x\right)-2}{2\cos\left(x\right)-1}\right)$ by replacing all occurrences of $x$ by $1$

$\frac{2\cdot \cos\left(1\right)^2+3\cos\left(1\right)-2}{2\cos\left(1\right)-1}$

Final answer to the exercise

$\frac{2\cdot \cos\left(1\right)^2+3\cos\left(1\right)-2}{2\cos\left(1\right)-1}$

Try other ways to solve this exercise

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  • Solve using L'Hôpital's rule
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  • Solve using limit properties
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  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
  • Product of Binomials with Common Term
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Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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