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Exercise

$\lim_{x\to2}\left(\frac{sin\left(\pi\right)}{\ln\left(x-1\right)}\right)$

Step-by-step Solution

1

The sine of $\pi $ equals $0$

$\lim_{x\to2}\left(\frac{0}{\ln\left(x-1\right)}\right)$
2

Zero divided by anything is equal to zero

$\lim_{x\to2}\left(0\right)$
3

The limit of a constant is just the constant

0

Final answer to the exercise

0

Try other ways to solve this exercise

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  • Solve using L'Hôpital's rule
  • Solve without using l'Hôpital
  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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$\lim_{x\to-4}\left(\frac{x+4}{x^2-16}\right)$

Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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