The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: $\displaystyle\frac{a^2-b^2}{a+b}=a-b$.
Evaluate the limit $\lim_{x\to2}\left(x^3+8\right)$ by replacing all occurrences of $x$ by $2$
Calculate the power $2^3$
Add the values $8$ and $8$
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