$\frac{1}{\left(6+x\right)^3}$
$x^2+8x+8=3x+2$
$4x^2-8x+1=0$
$\int\frac{1}{\sqrt[4]{x}}dx$
$\left(7+x\right)^2+\left(7-x\right)^2\le130$
$\log\left(x^2-1\right)-\log\left(x+2\right)=2$
$\left(-3469\right)\cdot6$
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