$\lim_{x\to-3}\frac{x^3-9x}{x^2-3x}$
$\frac{x^2+1}{x^2-1}$
$0,087+0,001$
$\left(x-6\right)\left(x+6\right)\left(x-1\right)\left(x+1\right)$
$6^{-2}\cdot6^4$
$\left(\sqrt[5]{a}\right)^5$
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