$\lim_{x\to0}\left(\frac{9e^{3x}-9}{sin\left(x\right)}\right)$
$\lim\:_{x\to\:32}\left(\frac{1+6x}{1+2x}\right)^{\frac{1}{x}}$
$\sec^2x-2\tan x$
$\:\left(3xy-5\right)\left(4xy-2\right)$
$22-9\left(x+3y\right)-\left(x+3y\right)^2$
$\left(17x+4\right)\left(17x-4\right)$
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