x2−16x+8x^2-16x+8x2−16x+8
(1−k)3\left(1-k\right)^3(1−k)3
(x3−7)(x3−11)\left(x^3-7\right)\left(x^3-11\right)(x3−7)(x3−11)
dydx+1=−yx\frac{dy}{dx}+1=\frac{-y}{x}dxdy+1=x−y
limx→∞(3x+24x3+6)\lim_{x\to\infty}\left(\frac{3x+2}{4x^3+6}\right)x→∞lim(4x3+63x+2)
6r−5r+2r−3r+4r=86r-5r+2r-3r+4r=86r−5r+2r−3r+4r=8
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