$60\cdot840$
$\left(3a+b\right)\left(2a-4b\right)$
$3\sqrt{5}^2$
$5a^{3\:}+\:4a^3-9a^3$
$\frac{m^2}{m^2+9m-10}.\left(m^2+9m-10\right)$
$\:\frac{3x+2}{5}\:<x-4$
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