$-x^2+9y+x^2-8y$
$\frac{d}{dt}y=y$
$\frac{6x}{\left(x^2+3\right)^2}$
$\int\:\left(x^2-3x\right)^3\left(2x-3\right)dx$
$0.5+\frac{1}{2}$
$2=5$
$\int\:\:\left(8-5x\right)^3e^{\frac{x}{2}}dx$
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