Exercise
log(yx510)
Step-by-step Solution
1
The difference of two logarithms of equal base b is equal to the logarithm of the quotient: logb(x)−logb(y)=logb(yx)
log(10x5)−log(y)
2
Use the product rule for logarithms: logb(MN)=logb(M)+logb(N), where M=x5 and N=10
log(x5)+log(10)−log(y)
3
Use the following rule for logarithms: logb(bk)=k
log(x5)+21−log(y)
4
Using the power rule of logarithms: loga(xn)=n⋅loga(x)
5log(x)+21−log(y)
Final answer to the exercise
5log(x)+21−log(y)