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Exercise

$\log\left(x+1.5\right)=\log\left(x\right)$

Step-by-step Solution

1

For two logarithms of the same base to be equal, their arguments must be equal. In other words, if $\log(a)=\log(b)$ then $a$ must equal $b$

$x+1.5=x$
2

Move everything to the left hand side of the equation

$x+1.5-x=0$
3

Cancel like terms $x$ and $-x$

$1.5=0$
4

$1.5$ is not equal to $0$

false

Final answer to the exercise

false

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Similar Questions Solved

$\log\left(x\right)=3$

$2log\left(x\right)-log\left(x+6\right)=0$

$\log_3\left(x+4\right)+\log_3\left(x-4\right)=2$

$\log\left(4X^2\right)=128$

$\log_x\left(64\right)=3$

$\log_2\left(x-2\right)+\log_2\left(x+1\right)=2$

$2\cdot log\left(x\right)-1\cdot log\left(x+6\right)=0$

Main Topic: Logarithmic Equations

Are those equations in which the unknown variable appears within a logarithm.

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