$2cos^2\theta\:-5cos\theta\:+2=0$
$\int\left(2x-4\right)cos\left(3x\right)dx$
$\frac{d}{dx}\:in\sqrt[5]{4-3x^5}$
$\lim_{x\to\infty}\left(ln\left(1+x^2\right)-ln\left(1+x\right)\right)$
$-343\cdot2401$
$5\sin^2+2\cos^2-3=0$
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