cos(x)sin(x)tan(x)=1\frac{\cos\left(x\right)}{\sin\left(x\right)\tan\left(x\right)}=1sin(x)tan(x)cos(x)=1
3x3−5x3+4x+1\frac{3x^3-5x^3+4}{x+1}x+13x3−5x3+4
∫33x dx\int_3^3x\:dx∫33xdx
(1x−1)2\left(\frac{1}{x}-1\right)^{2}(x1−1)2
ddx y2−4x5+6xy−6x=6\frac{d}{dx}\:y^2-4x^5+6xy-6x=6dxdy2−4x5+6xy−6x=6
(9x2+5x)2\left(9x^2+5x\right)^2(9x2+5x)2
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