Exercise
$\log\left(x^2-1\right)-\log\left(x+1\right)=1$
Step-by-step Solution
Learn how to solve properties of logarithms problems step by step online. Solve the logarithmic equation log(x^2+-1)-log(x+1)=1. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: \displaystyle\frac{a^2-b^2}{a+b}=a-b.. Express the numbers in the equation as logarithms of base 10. Any expression to the power of 1 is equal to that same expression.
Solve the logarithmic equation log(x^2+-1)-log(x+1)=1
Final answer to the exercise
$x=11$