Exercise
$\log_{x+4}\left(3x^2+4x\right)=2$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the logarithmic equation logx+4(3*x^2+4*x)=2. Factor the polynomial 3x^2+4x by it's greatest common factor (GCF): x. Change the logarithm to base 10 applying the change of base formula for logarithms: \log_b(a)=\frac{\log_{10}(a)}{\log_{10}(b)}. Since \log_{10}(b)=\log(b), we don't need to write the 10 as base. Multiplying polynomials x and 3x+4. Multiply both sides of the equation by \log \left(x+4\right).
Solve the logarithmic equation logx+4(3*x^2+4*x)=2
Final answer to the exercise
$x=-2,\:x=4$