Final answer to the problem
$-1$
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1
The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
$\log_{2}\left(1\right)-\log_{2}\left(2\right)$
Learn how to solve properties of logarithms problems step by step online. Simplify log2(1/2) applying logarithm properties. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). If the argument of the logarithm (inside the parenthesis) and the base are equal, then the logarithm equals 1. Evaluating the logarithm of base 2 of 1. Subtract the values 0 and -1.
Final answer to the problem
$-1$
