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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log_{3}\left(\frac{x+25}{x-1}\right)=3$
Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation log3(x+25)-log3(x+-1)=3. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Rewrite the number 3 as a logarithm of base 3. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. Calculate the power 3^3.