$\left(x-4\right)\left(x+4\right)-x^2+16$
$-50\:x-10$
$\left(y^2+xy\right)dx+\left(x^2-xy\right)dy=0$
$\frac{\left(\:x^3+5x^2+16x+30\right)}{\left(x^2+2x+10\right)}$
$-x^2-12x+9$
$\left(\frac{v^5}{yv^8}\right)$
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