$\log\left(x-1\right)=\log\left(e^2-1\right)$

$\int\frac{5x^2+20x+6}{\left(x^2+1\right)}dx$

$\lim_{x\to+3}\:\frac{1}{x-3}-\frac{1}{x^2-x-6}$

$\int_0^2\left(x^5+5x+29\right)e^xdx$

$\lim_{x\to\infty}\left(x\cdot e^{\left(1-x\right)}\right)$

$2^{x^2+25x-28}=16^{6x-4}$