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Exercise

$\sec\left(x\right)=\tan\left(145.3\right)\csc\left(-19\right)$

Step-by-step Solution

1

Calculating the tangent of $145.3$ degrees

$\sec\left(x\right)=-0.6924\csc\left(-19\right)$
2

Calculating the cosecant of $-19$ degrees

$\sec\left(x\right)=-0.6924\cdot -3.0716$
3

Multiply $-0.6924$ times $-3.0716$

$\sec\left(x\right)=2.1268$
4

This equation has no solutions in the real plane

$No solution$

Final answer to the exercise

$No solution$

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