$\left(5a^2x+3b^3\right)^2$
$t^2+2t-43=0$
$12+36+15x-3-6x\left(-9\right)$
$\left(4x^3+3x+5x^2+9\right)+\left(4x^4-3x^32x^2-x-9\right)$
$\left(-\frac{3}{4}n-\frac{3}{8}n\right)$
$\frac{dc}{df}=-\frac{c^2f}{10}$
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