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Exercise

$\sin\left(65^{\circ}\right)\sin\left(20'\right)$

Step-by-step Solution

1

Apply the trigonometric identity: $\sin\left(a\right)\sin\left(b\right)$$=\frac{\cos\left(a-b\right)-\cos\left(a+b\right)}{2}$, where $a=65$ and $b=20^{\prime}$

$\frac{\cos\left(65- 20^{\prime}\right)-\cos\left(65+20^{\prime}\right)}{2}$

Final answer to the exercise

$\frac{\cos\left(65- 20^{\prime}\right)-\cos\left(65+20^{\prime}\right)}{2}$

Try other ways to solve this exercise

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  • Find the derivative
  • Integrate using basic integrals
  • Verify if true (using algebra)
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  • Product of Binomials with Common Term
  • FOIL Method
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Main Topic: Simplify Trigonometric Expressions

Simplification of trigonometric expressions consists of rewriting an expression with trigonometric functions in a simpler form. To perform this task, we usually use the most common trigonometric identities, and some algebra.

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