Final answer to the problem
$\frac{\sqrt{x^{5}-x^2y^3+2yx^{4}-2y^{4}x+y^2x^3-y^{5}}x^2-\sqrt{x^{5}-x^2y^3+2yx^{4}-2y^{4}x+y^2x^3-y^{5}}y^2}{4\sqrt{x+y}\sqrt{x^2+xy+y^2}}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Product of Binomials with Common Term
- FOIL Method
- Find the integral
- Find the derivative
- Factor
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Load more...
Can't find a method? Tell us so we can add it.
1
Multiplying the fraction by $\sqrt{\frac{\frac{x^3-y^3}{x+y}\left(x^2+2xy+y^2\right)}{x^2+xy+y^2}}$
$\frac{\left(x^2-y^2\right)\sqrt{\frac{\left(x^3-y^3\right)\left(x^2+2xy+y^2\right)}{\left(x+y\right)\left(x^2+xy+y^2\right)}}}{4}$
Learn how to solve definite integrals problems step by step online.
$\frac{\left(x^2-y^2\right)\sqrt{\frac{\left(x^3-y^3\right)\left(x^2+2xy+y^2\right)}{\left(x+y\right)\left(x^2+xy+y^2\right)}}}{4}$
Learn how to solve definite integrals problems step by step online. Expand the expression (((x^3-y^3)/(x+y)(x^2+2xyy^2))/(x^2+xyy^2))^1/2(x^2-y^2)/4. Multiplying the fraction by \sqrt{\frac{\frac{x^3-y^3}{x+y}\left(x^2+2xy+y^2\right)}{x^2+xy+y^2}}. Multiplying polynomials x^3-y^3 and x^2+2xy+y^2. Multiplying polynomials x^2 and x^3-y^3. Multiplying polynomials x^3-y^3 and 2xy+y^2.
Final answer to the problem
$\frac{\sqrt{x^{5}-x^2y^3+2yx^{4}-2y^{4}x+y^2x^3-y^{5}}x^2-\sqrt{x^{5}-x^2y^3+2yx^{4}-2y^{4}x+y^2x^3-y^{5}}y^2}{4\sqrt{x+y}\sqrt{x^2+xy+y^2}}$