$\left(4u-8+3v\right)\left(4u+5v-8\right)$
$\frac{-3x^4+4x^3-6x^2-5}{x^2-2x+4}$
$\int\left(5x+5\right)sen\:\left(2x^{2\:}+4x\:+\:10\right)dx$
$f\left(x\right)=\left(2x^2+3\right)\left(\sqrt{x}-2\right)$
$3-\left(-4\right)$
$\frac{x^2+3x-2}{x+1}$
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