dydx=xy+x+t+1\frac{dy}{dx}=xy+x+t+1dxdy=xy+x+t+1
4a4=2a34a^4=2a^34a4=2a3
(3x3−6x2−9x−18)(3x−1)\frac{\left(3x^3-6x^2-9x-18\right)}{\left(3x-1\right)}(3x−1)(3x3−6x2−9x−18)
14mn+7my14mn+7my14mn+7my
∫x3+3(x3+4x2+4x)dx\int\frac{x^3+3}{\left(x^3+4x^2+4x\right)}dx∫(x3+4x2+4x)x3+3dx
limh→∞h2−h−6h3−3h2+h−3\lim_{h\to\infty}\frac{h^2-h-6}{h^3-3h^2+h-3}h→∞limh3−3h2+h−3h2−h−6
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