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Exercise

$\sqrt{2y}+x^{2y}-x^{\frac{y}{2}};\:x=2$

Step-by-step Solution

1

The power of a product is equal to the product of it's factors raised to the same power

$\sqrt{2}\sqrt{y}+x^{2y}-x^{\frac{y}{2}},\:x=2$
2

Calculate the numerical value for $\sqrt{2}\sqrt{y}+x^{2y}-x^{\frac{y}{2}}$ when $x=2$. Replace the unknowns with their corresponding values

$\sqrt{2}\sqrt{y}+2^{2y}- 2^{\frac{y}{2}}$

Final answer to the exercise

$\sqrt{2}\sqrt{y}+2^{2y}- 2^{\frac{y}{2}}$

Try other ways to solve this exercise

  • Choose an option
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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Main Topic: Numerical value of an algebraic expression

The numerical value of an algebraic expression is the result obtained by substituting the variables by a numerical value given.

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