$\left(\sqrt[3]{h+1}\right)\left(\sqrt[3]{h+1}\right)^2$

$\frac{d}{dx}\:\frac{\left(x^2-7\right)}{e^x}$

$\frac{8x^5+1}{2x^2-1}$

$\lim_{x\to+\infty}\left(\frac{e^{\frac{8}{x}-1}}{\frac{9}{x}}\right)$

$\frac{6}{7}+y\ge6$

$6^{10}.6^6$