∫(z3)(z−1)3dx\int\frac{\left(z^3\right)}{\left(z-1\right)^3}dx∫(z−1)3(z3)dx
3m2−3m+18=03m^2-3m+18=03m2−3m+18=0
ddx((x2−4)3(5x+3)2)\frac{d}{dx}\left(\frac{\left(x^2-4\right)^3}{\left(5x+3\right)^2}\right)dxd((5x+3)2(x2−4)3)
3bb(b+3)−2b−3b(b+3)\frac{3b}{b\left(b+3\right)}-\frac{2b-3}{b\left(b+3\right)}b(b+3)3b−b(b+3)2b−3
dydx(x+1)=xy\frac{dy}{dx}\left(x+1\right)=xydxdy(x+1)=xy
y′−yx=−1y'-\frac{y}{x}=-1y′−xy=−1
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