$\int\frac{2x^2-6x+5}{\left(x+1\right)^2\left(x-2\right)^3}dx$
$x+y=-2$
$\left(cot\theta\:\right)\left(cot\theta\:-tan\theta\:\right)$
$3x\:=\:-x\:+\:16$
$\left(10^3\right)^5$
$-6x^{2}y^{3}\left(-3xy^{2}\right)$
$2x^3+5x^2-7$
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