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Exercise

$\tan\left(\arctan\left(17\pi\right)\right)$

Step-by-step Solution

1

Since arctan is the inverse function of tangent, the tangent of arctangent of $17\pi $ is equal to $17\pi $

$17\pi $

Final answer to the exercise

$17\pi $

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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