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Exercise

$-\frac{4}{7}x+\left(-\frac{2}{7}x\right)+\frac{1}{7}$

Step-by-step Solution

1

Combining like terms $-\frac{4}{7}x$ and $-\frac{2}{7}x$

$-\frac{6}{7}x+\frac{1}{7}$

Final answer to the exercise

$-\frac{6}{7}x+\frac{1}{7}$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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