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Exercise

$-\frac{6}{5}-\frac{2}{3}v\:\frac{4}{15}+\frac{1}{3}v$

Step-by-step Solution

1

Combining like terms $-\frac{2}{3}\cdot \frac{4}{15}v$ and $\frac{1}{3}v$

$-\frac{6}{5}-\frac{1}{3}v$

Final answer to the exercise

$-\frac{6}{5}-\frac{1}{3}v$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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