$56:-11$
$\frac{\cos\left(x\right)\tan\left(x\right)}{\sin\left(x\right)}=\sec^2\left(x\right)-\tan\:^2\left(x\right)$
$10x+6=4y$
$x1ny+sin\:3x$
$\left(5a-20b\right)^2$
$x^2+9\ge0$
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