(4x2+3)⋅(2x−3)\left(4x^2+3\right)\cdot\left(2x-3\right)(4x2+3)⋅(2x−3)
(3−8)+(5−(−2))+6−5+412\left(3-8\right)+\left(5-\left(-2\right)\right)+6-5+412(3−8)+(5−(−2))+6−5+412
5x−6>115x-6>115x−6>11
limx→∞(x(logx(x))(logx(x)))\lim_{x\to\infty}\left(\frac{x}{\left(\log_x\left(x\right)\right)^{\left(\log_x\left(x\right)\right)}}\right)x→∞lim((logx(x))(logx(x))x)
4 x − 6 > 6x4\:x\:-\:6\:>\:6x4x−6>6x
2x−y=122x-y=122x−y=12
∫0xyexdx\int_0^x\frac{y}{e^x}dx∫0xexydx
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