$x^3-1-x^5+x^2$
$\frac{1}{2}\int1\:+\:tan^2\left(u\right)\:sec\:^2\left(u\right)du$
$\frac{dy}{dx}=\ln\left(x\right)\cdot\sqrt{16-y^2}$
$\log_{144}\left(12\right)=2$
$-6y^2-12xy+4x^2$
$-16t^2+64t+160$
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