1cos2x−tan2x=1\frac{1}{\cos^{2}x}-\tan^{2}x=1cos2x1−tan2x=1
∫x2+x−7(2x−3)(x2+4)dx\int\frac{x^2+x-7}{\left(2x-3\right)\left(x^2+4\right)}dx∫(2x−3)(x2+4)x2+x−7dx
∫49−y2ydy\int\frac{\sqrt{49-y^2}}{y}dy∫y49−y2dy
(11x−9)(−9−11x)\left(11x-9\right)\left(-9-11x\right)(11x−9)(−9−11x)
xy+xy2+x3y=7y2xy+xy^2+x^3y=7y^2xy+xy2+x3y=7y2
(−52)+(−48)−(+34)−(53)\left(-52\right)+\left(-48\right)-\left(+34\right)-\left(53\right)(−52)+(−48)−(+34)−(53)
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