$\frac{du}{dr}=\frac{2+\sqrt{r}}{5+\sqrt{u}}$
$3xy\:dx\:+\left(4+x^2\right)\:dy\:=\:0$
$9x\:+\:10x\:-\:12\:+\:a\:-\:b\:+\:ab$
$\frac{dy}{dx}=\frac{x+4}{1+y}$
$1x^2+6x+5$
$lg\:x=5.1$
$\lim_{x\to6}\left(\frac{x^2+4x+3}{x+3}\right)$
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