$7v-7+7-8v$
$5x+4y;\:x=1;\:y=-4$
$\int\frac{x^3-2}{x^2-4x+4}dx$
$x^2-7x+12=0$
$\frac{\left(1^{23}-3^3\right)}{\left(-2\right)}$
$\int\frac{x^2+6}{\left(x-1\right)^2}dx$
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